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X^2-46X-360=0
a = 1; b = -46; c = -360;
Δ = b2-4ac
Δ = -462-4·1·(-360)
Δ = 3556
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3556}=\sqrt{4*889}=\sqrt{4}*\sqrt{889}=2\sqrt{889}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-46)-2\sqrt{889}}{2*1}=\frac{46-2\sqrt{889}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-46)+2\sqrt{889}}{2*1}=\frac{46+2\sqrt{889}}{2} $
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